[Resolved] ()= or []=

[Aran]

I'm not sure which one I saw, but I was competely lost when I saw a method name as this: ()= or, this []= (one of them)

in other words, what does:

def []= #or, ()=
#blah
end

 

[Anonymous]

It was []=, and it defines the operator [] for use with objects of that type. It's usually used for array wrapper data types.

Look at Game_Actors:

class Game_Actors
  #--------------------------------------------------------------------------
  # * Object Initialization
  #--------------------------------------------------------------------------
  def initialize
    @data = []
  end
  #--------------------------------------------------------------------------
  # * Get Actor
  #     actor_id : actor ID
  #--------------------------------------------------------------------------
  def [](actor_id)
    if actor_id > 999 or $data_actors[actor_id] == nil
      return nil
    end
    if @data[actor_id] == nil
      @data[actor_id] = Game_Actor.new(actor_id)
    end
    return @data[actor_id]
  end
end

$game_actors is not an array, but you can use $game_actors to access the actors at the various indices just like an array thanks to the #[] method.

[]= would allow you to assign the object to an array. For example, if we were adding that method to a class:

class Foo
  def initialize
    @data = []
  end

  def []=(somearray)
    @data = somearray
  end

  def [](i)
    return @data[i]
  end
end

We could then do this:

foo = Foo.new
foo = [1, 2, 3, 4]
print foo[1]  # prints "2"
foo = []

And so on.

 

[Aran]

*tear comes to eye* beautiful...

I'm learning a lot today... already...

thanx, ccoa. I would believe its resolved now... unless someone else wants to reply... I guess...

 

[SephirothSpawn]

This topic has been resolved. If Aran or any other users have any questions or further problems regarding this topic, please create a new thread about them.

Thank you!