Not a request, just didn't want to post in Script Submission.

[Tsunokiette]

I posted a method to return if a number is odd or not a while ago somewhere, and it got butch... *cough* enhanced :D and I learned a few things.

Now I once again post an almost useless method, except now it works with any number of arguements and will return the result in an array unless there is only one number .... or none. It will also allow any number of arrays and any combination of arrays and singular numbers.

If you use an array as an arguement, then the result will be in -

local_variable[index_of_array,index_of_result]

Here's the method -

def odd?(*numbers)
   if *numbers.size == 1 and !*numbers[0].is_a?(Array)
      result = (*numbers[0] % 2 = 1)
   elsif *numbers.size == 1 and *numbers[0].is_a?(Array)
      for i in 0...*numbers[0].size
         result[i] = (*numbers[0,i] % 2 = 1)
      end
   elsif *numbers.size == 0
      return p "No numbers provided for 'odd?' method."
   else
      for i in 0...(*numbers.size)
         if *numbers[i].is_a(Array)
            for j in 0...(*numbers[i].size)
               result[i,j] = (*numbers[i,j] % 2 = 1)
            end
         else
            result[i] = (*numbers[i] % 2 = 1)
         end
      end
   end
   return result
end

To use make sure you allays use a variable of some sort.

IE:

number_odd = odd?(some_array,3,2,89,another_array)

EDIT : Realized a small error, fixed now.

 

[Sheol]

I'm sure you can make it smaller, again, but I can't do it this time, because my computer isn't working...

 

[Tsunokiette]

It's possible, but I can't do it. Everytime I post something, I get to learn new ways to optimize code.

^_^

 

[verballydecapitating]

def odd?(num)
	case int.class.to_s
	when 'Fixnum'
		return unless (num % 2) == 0
	when 'Array'
		amt = 0
		for i in 0..num.size - 1
			amt + 1 unless (num[i] % 2) == 0
		end
		return amt
	end
end

If used on a fixnum returns if it's odd or not, if used on array returns how many are odd. Don't think it works, never tested it.