[Resolved]-Cutting back a decimal value

[Kain Nobel]

Thank you both for helping me, both methods work pretty well!

darkleo's method works for having a value between .0 and .00000000000000, just change the +m to how many decimals you want left over, but sometimes it'll cut it off to just 1 decimal digit when using thousand+ valued numbers.

Spoiler: Darkleo's method in work within $game_variables

class Game_Variables
  #--------------------------------------------------------------------------
  # * Set Variable
  #     variable_id : variable ID
  #     value       : the variable's value
  #--------------------------------------------------------------------------
  def []=(variable_id, value)
    if variable_id <= 5000
      if value.is_a?(Float)
        @value = value
        @decimals = @value.to_i.size + 1
        value = @value.to_s[0, 2+@decimals].to_f
      end
      @data[variable_id] = value
    end
  end
end

kmhp's method however will always have the specified decimal ammount, as long as the last values aren't 0!

Spoiler: Darkleo's method in work within $game_variables

class Game_Variables
  #--------------------------------------------------------------------------
  # * Set Variable
  #     variable_id : variable ID
  #     value       : the variable's value
  #--------------------------------------------------------------------------
  def []=(variable_id, value)
    if variable_id <= 5000
      if value.is_a?(Float)
        value = sprintf('%.2f', value).to_f 
      end
      @data[variable_id] = value
    end
  end
end

I shall now label this topic as "Resolved"  :thumb:

Spoiler: Origional Question

How do you cut back a decimal value? For instance, when tracking Player's Screen Y, sometimes the value will show 260.35745572234523457.

How do I cut it so it only shows, like 260... or 260.3... or 260.35?

I searched the help file and tried screen_x.truncate, but it didn't do anything but error pop for me.

 

[darkleo]

  n = 3.1415926535897932384626433832795028841971
  m = n.to_i.to_s.size + 1
  n = n.to_s[0, 5+m].to_f
  p n

n is PI. (yeah !)
The last line return PI with 5 numbers after the "."

 

[Kain Nobel]

Definately a functional method, isn't there a simpler one though? Reguardless, this works just fine for what I needed it for, its just kinda confusing.

Everythings working great now, thank you for helping me out! :thumb:

 

[khmp]

You could try something like this.

float_number = 5.323423425
p sprintf('%.2f', float_number).to_f # 5.32
float_number = 5.3
p sprintf('%.2f', float_number).to_f # 5.3

Good luck with it Kain Nobel! :thumb:

 

[Kain Nobel]

Cool, that works even better and I understand it! Thanks to both of you for helping me out!